Arithmetic instructions

 # include<stdio.h>

# include <math.h>

int main(){

    int a = 4;

    int b = 8;

    printf("The value of a + b is: %d\n", a + b);

    printf("The value of a - b is: %d\n", a - b);

    printf("The value of a * b is: %d\n", a * b);

    printf("The value of a / b is: %d\n", a / b);

    int z;

    z = b * a; // legal

    //b * a = z; // Illegal

    printf("The value of z is: %d\n", z);

    printf("5 when divided by 2 leaves a remainder of %d\n", 5%2);

    printf("-5 when divided by 2 leaves a remainder of %d\n", -5%2);

    printf("5 when divided by -2 leaves a remainder of %d\n", 5%-2);

    // No operator is assumed to be present

    //printf("The value of 4 * 5 is %d\n", (4)(5)); --> Will not return 20/ Wrong!!

    printf("The value of 4 * 5 is %d\n", (4)*(5));

    // There is no operator to perform exponentiation in C

    printf("The value of 4 ^ 5 is %d\n", 4^5); // -> Will not produce 4 to the power 5

    printf("The value of 4 to the power 5 is %f\n", pow(2, 5)); 

    printf("The value of 6 + 5 is %d\n", 6 + 5);

    printf("The value of 6 + 5.6 is %f\n", 6 + 5.6);

    printf("The value of 6.1 + 5.6 is %f\n", 6.1 + 5.6);

    printf("The value of 5/2 is %d\n", 5/2);

    printf("The value of 3.0/9 is %f\n", 3.0 / 9);

    return 0;

    

}